How many different numbers which are smaller than
2.10^8
can be formed using the digits 1 and 2 only?
Answers
Answered by
0
Answer:
What are the number of natural numbers which are smaller than 2*10^8 and which contain only the digits 1 and 2?
Save taxes & secure your family's future, with a term plan.
Question: What are the number of natural numbers which are smaller than 2*10^8 and which contain only the digits 1 and 2?
Solution:
Break the question into many parts by number of digits:
Single digit numbers = C1=2=1, 2
2-digit numbers: C2=2∗2=4 [ ∵ First digit in 2 ways, second digit in 2 ways ]
3-digit numbers: C3=2∗2∗2=8
4-digit numbers: C3=2∗2∗2∗2=16
….
8 digit numbers: C8=28=256
9 digit numbers: C9=1∗28=256 [ ∵ the first digit can only be 1 so that the number will be less than 2∗108 ]
Total numbers that can be made = ∑i=19Ci
=2+4+8+16+...+256+256=766
Similar questions