Math, asked by Gauravbhardwaj5186, 11 months ago

How many different positive integer factors does (64)(81)(125) have?

Answers

Answered by Saiparthi
0

Answer:

8*8=64

9*9=81

5*5*5=125

there r 1 positive integer factors

Answered by windyyork
0

Answer: The different positive integer factors are 140.

Step-by-step explanation:

Since we have given that

(64)(81)(125).

We can rewrite it as

64=2^6\\\\81=3^4\\\\25=5^3

As we know that to find the different positive integer factors, we get that

(6+1)(4+1)(3+1)\\\\=7\times 5\times 4\\\\=140

Hence, the different positive integer factors are 140.

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