Question

How many different two-digit numbers can you form using the digits 7 comma 5 comma 3 comma 8 comma 6 comma 2 comma and 9 without repetition? For example, 33 is not allowed.

Answer 1

75,38,62,97 is your answer

Answer 2

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$\large\red{Question:}$

How many different two-digit numbers can you form using the digits 7, 5, 3, 8, 6, 2 & 9 without repetition?


$\huge\red{Answer:}$
Available digits : 7, 5, 3, 8, 6, 2 & 9
Number of Available digits = 7

----To form a two digit Number---

The first digit can be filled in 7 possible ways

As we have to form two digit number without repetition, we have left with 6 Available digits, as we aren't allowed to use the first digit again

The second digit can be filled in 6 possible ways


Therefore,
The Number of ways possible for the formation of two digit number using available digits = 7×6 = 42

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