Question

How many different ways can be there to arrange the letters of the word 'canne' such that the vowels always come together?

Answer 1

Canne has 5 letters to split up the vowels we have 4. Vowels count on as 1. So..
- ae is 2!
- Cnn is 3!/2!
So canne is 2! x 3!/2! = 3! = 3 x 2 = 6

Answer 2

Answer:

Step-by-step explanation:

CANNE is the word, having A, E vowels and NN is same letter (repeated)

AECNN , CAENN, CNAEN, CNNAE , so vowels together can be placed in 4! ways ( total no of letters - no of letters together +1 ) = 4!

AE can be interchanged as EA i.e 2! ways

NN is repeated and we lose the arrangement of 2! ways

so answer = 4! 2! / 2! = 24