Question

How many different words can be formed with the letter M taken twice, the letter P taken thrice and the letter R taken twice?

Answer 1

Answer:

210

Step-by-step explanation:

Hi,

Since the collection of letters are

M  2,P 3 and R 2.

In total, there are 7 letters

So we can arrange 7 letters in 7! ways.

But since M is repeating twice and all permutations between M'

result in same arrangement, we need to divide by 2!,

Similarly, since P is repeating thrice and all permutations

between P' result in same arrangement, we need to divide by 3!,

Since R is repeating twice and all permutations between R'

result in same arrangement, we need to divide by 2!,

So, total number of arrangements are 7!/3!2!2!

= 5040/24

= 210

Hope, it helps !