Question

how many different words can be formed with the letters of the word EQUATION so that the word begin with E? ​

Answer 1

Step-by-step explanation:

8 letters i.e. 3 consonants 5 vowels.

The consonants are to occupy 1st and last place and it can be done in 3P2 ways. We will now be left with 5 vowels and 1 consonant i.e. 6 letters which can be arranged in 6! ways. Hence the number of words under given condition is

3P2×6!=6×720=4320.

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Answer 2

Answer:

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