How many different words of 4 letter can be formed with the letter of examination
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find no. of combinations and permutations of the 4 letter taken from the word "EXAMINATION" (AA), (II), (NN), E, X, M, T, O. Hence required number of combinations = 3 +63 +70 = 136. Hence required number of permutations = 18 +756 +1680 = 2454.
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