Question

how many digits are there in the expression 6 ki power 2 into 2 ki power 98 into 5 ki power 99 ​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

The number of digits are 101 in $6^2\times 2^{98}\times 5^{99}$

Step-by-step explanation:

Given : Expression $6^2\times 2^{98}\times 5^{99}$

To find : How many digits are there in the expression ?

Solution :

Expression $6^2\times 2^{98}\times 5^{99}$

Multiply and divide by 2,

$6^2\times 2^{98}\times 5^{99}\times \frac{2}{2}$

$\frac{36}{2}\times 2^{99}\times 5^{99}$

$18\times (2\times 5)^{99}$

$18\times (10)^{99}$

The number of digits in the expression is 2(1,8)+99(0's)=101

Therefore, The number of digits are 101 in $6^2\times 2^{98}\times 5^{99}$