Math, asked by Nitesh1503, 11 months ago

How many digits between 5000 and 7000 can be formed using the digits 3 to 8, when any digit can occur any number of times?​

Answers

Answered by RitaNarine
6

The Numbers between 5000 and 7000 can be formed using the digits 3 to 8, when any digit can occur any number of times is 432.

Given all the numbers should lie between 5000 and 7000.

  • Therefore , number at 1000's place have 2 possibilities ,can be 5 and 6 .
  • Numbers at the 100s , 10s and units place can be between 3 and 8 .
  • Since it can occur any number of times,
  • 100s place can have 6 possibilities.
  • 3 , 4, 5 ,6 , 7 and 8 .
  • 10s place also have 6 possibilities and
  • Units place can also have 6 possibilities.
  • Therefore total numbers = 2 x 6 x 6 x 6 = 2 x 6³ = 432
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