Question

how many digits between 5000 and 7000 can beformdusing 3 to 8, when any digit can occurany number of times
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Answer 1

Given that a number is to be formed between 5000 and 7000 using the digits 3 to 8.

The first digit of the number can have the digits 5 or 6. The first digit has two possibilities.

The second digit of the number can have any digit between 3 to 8. The second digit has 6 possibilities.

The third digit of the number can also have any digit between 3 to 8. The third digit has 6 possibilities.

Similarly the fourth digit of the number has 6 possibilities.

Total possible numbers = 2×6×6×6 = 432

Answer 2

Given :

Numbers are to be formed Using 3,4,5,6,7,8 between 5000 & 7000

To Find :

How many Numbers can be formed

between 5000 & 7000 using 3 ,4, 5

,6,7,8 .

Solution :

•Clearly , Numbers between 5000 and 7000 are 4 digits Number

so, only 4 digit Numbers greater than 5000 & less than 7000 can be made

•For 1st place only 5,6 can be selected

i.e. 2 digits can be used for first place .

•For 2nd place all the digits can be selected

i.e. 6 digits can be used for Second place

•For 3rd place all the digits can be selected

i.e. 6 digits can be used for Third place

•For 4rth place all the digits can be selected

i.e. 6 digits can be used for fourth place

•So, total Number of ways in which digits can be selected is 2×6×6×6 i.e. 432

•Hence 432 Numbers between 5000 to 7000 can be made using digits from 3 to 8