Math, asked by RatriSarkar, 11 months ago

How many digits in the square root of a perfect square number having n digits, whose n is an odd number.

Also, find the number of digits in 1522756pls solve​

Answers

Answered by Terry1987
1

Answer:

(n+1)/2. So, the number of digits in the square root of the given number is (7+1)/2= 4.

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