Math, asked by architanawadia972, 7 months ago

How many digits in the square root of a perfect square number having n digits, whose n is an odd number.
Also, find the number of digits in square root 1522756.


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Answers

Answered by prarthanap40
0

Answer:

number of digits is double

Answered by iampriyanka1
7

  \huge\mathfrak \red{solution}

 \frac{n + 1}{2}

So , square root of the given number has 4 digits.

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