Question

how many double digit numbers when divided by 3 gives a remainder of 2

Answer 1

Answer:

here is your answer

Step-by-step explanation:

there are 32 numbers which when divided by 3 gives the remainder 2 : 5,8,11,…….98.

Answer 2

Answer:

The number of double-digit numbers when divided by 3 gives the remainder 2 = 30

Step-by-step explanation:

Required to find,

The number of two-digit numbers when divided by 3 gives a remainder of 2

Recall the formula

The nth term of an AP = $a_n = a+(n-1)d,$ where 'a' is the first term and 'd' is the common difference

Solution:

The first two-digit number when divided by 3 gives the remainder 2 = 11

The second number in the set is 14

The set of two-digit numbers when divided by 3 gives the remainder 2 = {11,14,17,20,......................98}

This set form an AP with first term 11 and common difference 3 and

Here, last term = $a_n$ = 98

a+(n-1)d = 98

11+(n-1)3 = 98

3(n-1) = 98 -11 =87

n-1 = 29

n = 29+1

n= 30

Since 98 is the 30th term of the series, Hence there are 30 terms in the set

∴The number of double-digit numbers when divided by 3 gives the remainder 2 = 30

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