How many electric bulbs each rated as 100 W at 220 V are required
to be joined in parallel with the supply voltage of 220 V to draw 5 A
current from the service mains ?
Answers
Answer:
Question: 12. Several electric bulbs designed to be used on a 220 V electric supply line, are rated 10 W. How many lamps can be connected in parallel with each other across the two wires of 220 V line if the maximum allowable current is 5 A?
Answer:
Given, power = 10W
Potential difference, V = 220 V
Electric current, I = 5A
Here to calculate total number of bulbs, total resistance will be calculated.
We know that,
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Let, number of bulb connected into parallel = m
Let, total effective resistance, when m bulbs are connected in parallel = R1
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Therefore, total number of bulbs = 110 Answer
Question: 13. A hot plate of an electric oven connected to a 220 V line has two resistance coils A and B, each of 24 Ω resistance, which may be used separately, in series, or in parallel. What are the currents in the three cases?
Answer:
Case : 1: When coil is used separately, then
Resistance, R = 24 Ω and V = 220V
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Thus, in this case electric current, I = 9.16 A
Case : 2: When the two resistors are connected in series.
Total effective resistance in the series when coils are used in series= 24 Ω + 24Ω = 48 Ω
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Thus, in this case electric current, I = 4.58 A
Case : 3: When the two resistors are connected in parallel,
Let the total effective resistance = R
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(a) When coil is used separately the electric current (I) = 9.16A
(b) When coils are used in series the electric current (I)= 4.58 A
(c) When coils are used in parallel the electric current (I)= 18.33 A
Question: 14. Compare the power used in the 2 Ω resistor in each of the following circuits:
(i) a 6 V battery in series with 1 Ω and 2 Ω resistors, and
(ii) a 4 V battery in parallel with 12 Ω and 2 Ω resistors.
Answer:
(i) a 6 V battery in series with 1 Ω and 2 Ω resistors
The total effective resitance, R = 1 Ω + 2 Ω = 3 Ω
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Since, electric current remains the same when resistors are connected in series.
Therefore, electric current through the resistor of 2Ω = 2A
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(ii) a 4 V battery in parallel with 12 Ω and 2 Ω resistors
Since, voltage across the circuit remains same if resistors are connected in parallel.
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Power used by resistance of 2 Ω in both the case = 8 W