Question

How many electron flow through a metallic wire if a current of 0.5 a is passed for 2 hours?

Answer 1

Current = charge /time (I=q/t)
substituting I=0.5 A,t=2hrs =2*60*60=7200sec
0.5=q/7200
3600=q
charge of one elecron=1.6*10^-19
Hence,
no:of elecrons=3600/(1.6*10^-19)
Answer:225*10^20 electrons