How many electron in an atom with atomic number 30 can have (n + 1)=4?
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Answer:
30 electron
Explanation:
The atomic number of an atom is the number of electron present in that atom.So there the atomic number of atom is 30 then it has 30 electrons
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Correct Question:
How many electrons in an atom with atomic number 30 can have (n+l) = 4?
Correct Answer:
The no of electrons in an atom with atomic number 30 that can have (n+l)=4 is Eight (8).
- The electronic configuration of the atom is:
1s², 2s², 2p⁶, 3s², 3p⁶, 4s², 3d¹⁰
- We know that:
n = principal quantum number.
l = azimuthal quantum number.
- The (n + l) value for all the subshells are:
1s = 1 + 0 = 1
2s = 2 + 0 = 2
2p = 2 + 1 = 3
3s = 3 + 0 = 3
3p = 3 + 1 = 4
4s = 4 + 0 = 4
3d = 3 + 2 = 5
- So, there are only 2 subshells (3p and 4s) with (n+l) = 4
- 3p has 6 and 4s has 2 electrons.
- So, the total number of electrons = 6 + 2 = 8
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