How many electron pass 2minutes into if the current passing throw wire 300
Answers
Answered by
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HOLA AMIGO!!
HERE WE GO
GIVEN
Current = 300A
time (t) = 2min = 2×60 =120s
SOLUTION
we know I = Q/t = ne/t
where n = no.of electron and e= charge of electron = 1.609×10^-19
I = ne/t
n = It/e
= 300×120/1.609×10^-19
=36000/1.609×10^-19
= 3.3676
therefore n = 3.3676
HOPE IT'S HELPFUL
HERE WE GO
GIVEN
Current = 300A
time (t) = 2min = 2×60 =120s
SOLUTION
we know I = Q/t = ne/t
where n = no.of electron and e= charge of electron = 1.609×10^-19
I = ne/t
n = It/e
= 300×120/1.609×10^-19
=36000/1.609×10^-19
= 3.3676
therefore n = 3.3676
HOPE IT'S HELPFUL
Answered by
0
q = it
q= ne
it = ne
n = it/e
n = 300*2*60/1.6*10^-19
n = 36* 10^22/1.6
n = 9*10^22/.4 = 90/4*10^22 = 22.2*10^22 electrons...
q= ne
it = ne
n = it/e
n = 300*2*60/1.6*10^-19
n = 36* 10^22/1.6
n = 9*10^22/.4 = 90/4*10^22 = 22.2*10^22 electrons...
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