Question

how many electron pass through a wire in 1 min if current passing through the wire in 200mA​

Answer 1

Explanation:

Q=I×t

=200×10^-3 ×60

=12

Q=ne

n=Q÷e

n=12/1.6 ×10^-19

n=1.33×10^20 electrons

Answer 2

$\Large{\underline{\underline{\bf{Solution :}}}}$

We know that,

$\Large{\implies{\boxed{\boxed{\sf{I = \frac{Q}{t}}}}}}$

Where,

I = 200 mA = 200 $\times 10^{-3}$ = 0.2A

t = 60 s

_______________[Put Values]

$\sf{→0.2 = \frac{ne}{60} \: \: \: \: \: \: \implies ne = 12} \\ \\ \sf{→n = \frac{12}{1.67 \times 10^{-19}}} \\ \\ \sf{→n = 7.1 \times 10^{17} \: electrons}$