How many electrons are contained in 3.2*10^-6c of charge?
Answers
Answered by
1
Answer:
1.6 * 10^19 electrons
Explanation:
Answered by
3
Let n=number of electrons
Q = n*e
Charge of e = 1.6 * 10^-19
3.2*10^-19 = n * 1.6 * 10^-19
n = 3.2*10^-19/n * 1.6 * 10^-19
n = 2 * 10^13 electrons
Q = n*e
Charge of e = 1.6 * 10^-19
3.2*10^-19 = n * 1.6 * 10^-19
n = 3.2*10^-19/n * 1.6 * 10^-19
n = 2 * 10^13 electrons
Similar questions