How many electrons are delivered to the cathode during electrolysis by a current of 1 ampere for 193 seconds?
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3.75×1020
Q=ne
Q is the amount of electricity passed
n is the number of electrons liberaed at cathode
e the charge of electron
i×t=ne (Q=i×t)
n=ei×t
n=1.6×10−191×60
n=3.75×1020
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