Question

How many electrons are flowing per second past a point in a circuit in which there is a current of 5 ampere?

Answer 1

Hey friend
here is your answer

as,
1 Columb = 6.25 × 10^18

$1 \: columb (c)= 6.25 \times {10}^{18} electrons \\ and \\ 1ampere= \frac{1c}{1sec} \\ so \\ 5 \: ampere = \frac{ \: \: 6.25 \times {10}^{18} }{1} \times 5 \\ 5 \: ampere =31 .25\times \times {10}^{ 18} electrons.$





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hope it helps
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Answer 2

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