Question

how many electrons are flowing per second past a point in a circuit in which there is current of 5 ampere

Answer 1

Using,

$i = q \div t \\ q = i \times t$
q=5*1=5 coulomb
Now,


$q = n \times e \\ n = q \div e \\ \: \: \: \: \: \: \: \:n = 5 \div 1.6 \times {10}^{ - 19 } \\ \: \: \: \: \: n = 3.125 \times {10}^{22}$

Hope I helped