Question

how many electrons are flowing per second past a point in a circuit in which there is a current of 4A

Answer 1

as we know that Current formula I=Q/t
and also Q=n×e
by merging both formula
we get I=n×e/t
so we now the value of e= 1.6×10^-19
therefore 4A ×1sec/1.6×10^-19=n
I.e. n=2.5×10^19

Answer 2

Concept:

Current flowing in a wire can be defined as the charges flowing in per unit time.

i = Q/t

where i is current, Q is the charge and t is the time.

Given:

Current, i = 4 A

Time, t = 1 second

Find:

The total number of electrons flowing per second.

Solution:

As we know, the Charge of one electron is e = 1.6×10⁻¹⁹C

Total charge, Q=it, and Q = ne

Which can be written as,

ne = it

where n is the number of electrons.

ne = it

n (1.6×10⁻¹⁹) = (4 × 1)

n = 4 / 1.6×10⁻¹⁹

n = 2.5 ×10¹⁹

Hence, the total number of electrons in 4 A of current is 2.5 ×10¹⁹.

 

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