Physics, asked by lokesh1234, 1 year ago

how many electrons are possible in all shell with n+l=5?

Answers

Answered by rajatmishra7891
10

Answer:

18 maximum

Explanation:

n is greater than l

so here,(n+l)=5

5+0=5s—⟩1

4+1=4p—⟩2

3+2=3d—⟩3

2+3≠2f(not possible)

so

1-2electrons

2-6 electrons

3-10 electron

add all no of electrons and you will get 18

Hope this helps you

Answered by nirman95
1

Number of electrons possible with n+l = 5 is :

n + l = 5 can have many possibilities. Let's see:

  • n = 5 , l = 0 : orbital 5s [ Number of electrons will be 2]

  • n = 4 , l = 1 : orbital 4p [ Number of electrons will be 6]

  • n = 3 , l = 2 : orbital 3d [ Number of electrons will be 10]

  • n = 2 , l = 3 : orbital not possible (because l value is always n - 1 and cannot be greater than n)

So, total electrons possible is 2 + 6 + 10 = 18

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