Question

how many electrons are present in 0.1 moles of [po]4 - 3 ions

Answer 1

Answer:5

Explanation:

In 1 mol of [PO4]3- ,

No. of electrons =15+(8×4)+3=50

So in 0.1 mol of [PO4]3-,

No.of electrons =50×0.1=5

Answer 2

0.1 mole contains 5Na electrons.

Given,

No. of mole = 0.1 moles

To Find,

No electrons are present in 0.1moles of PO4-3.

Solution,

We can subsequently unravel the topics:

The amount of electrons in a neutral element is proportional to the number of protons.

• The atomic number of phosphorus is = 15 hence 15 electrons are present in phosphorus.
• The Atomic number of oxygen is 8 hence 8 electrons are present in the oxygen.

Now,

PO4-3 ions

No. of an electron in phosphorus =15

No. of an electron in four oxygen molecules = 4x8 = 32

Total No. of electrons in PO4- = 32 +15=47

Total No. of electrons in PO4-3 ion=47+3=50

1 ion of PO4-3 has 50 electrons.

There is 6.02 x 10^23 electrons present per mole.

Therefore, 0.1 moles of PO4-3 will comprise = 50×0.1x Na

= 5Na electrons.

Hence, 0.1 moles contain 5Na electrons.

#SPJ2