Question

How many electrons are present in 0.1 moles of [PO]4³- ions?
Anyone please explain and don't try to spam​

Answer 1

NO.OF MOLECULES = 0.1×6.023×10^23

= 6.023×10^22

NO. OF ATOMS =4×6.023×10^23

=24.029×10^23.

Answer 2

ans:(2)

Explanation:

1 molecule of [PO4]³- contains 15 + 4×8+3 = 50 e-

1mole contains 50×Na e-

0.1 mole contains 0.1×50×Na e-

= 5×Na