Question

how many electrons are present in 1.4 gram of dinitrogen gas.............

Answer 1

355 is the answer to your quesion

Answer 2

HÈLLØ!!

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$\Huge{\mathfrak{\blue{\underline{ANSWER}}}}$

Molar mass of dinitrogen (N2) = 28 g mol-1

Thus, 1.4 g of N2

= 1.4/28

= 0.05 mol

= 0.05 × 6.02 × 10²³ no of molecules

= 3.01 × 10²³ no. of molecules

Now, 1 molecule of N2 has 14 electrons.

Therefore, 3.01 × 10²³ molecules of N2 contains,

= 14 × 3.01 × 10²³

= 4.214 × 10²³ electrons.

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THÅÑKẞ!!