Question

How many electrons are present in 11g of Na​

Answer 1

6.023*10²³/2 this is the answer

Answer 2

We have to find the number of electrons are present in 11g of Na.

solution : Given mass of Na = 11 g

atomic mass of Na = 23 g/mol

no of moles of Na = 11/23 = 0.478

now no of atoms in 11g of Na = no of moles × 6.023 × 10²³

= 0.478 × 6.023 × 10²³

≈ 2.9 × 10²³

we know, in 11 electrons contain one atom of sodium element.

so, no of electrons in 11 g of Na = 11 × no of atoms in 11g of Na

= 11 × 2.9 × 10²³

= 31.9 × 10²³

= 3.19 × 10²⁴

≈ 3.2 × 10²⁴

Therefore the no of electrons in 11g of sodium is 3.2 × 10²⁴ (approx).

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