Question

How many electrons are present in 14 mg of N3 minus ions

Answer 1

Answer:

Nitrogen-Symbol-N -7(atomic number)

N³⁻ ion = 1s²2s²2p⁶

Total number of electrons =10

atomic mass of N=14

14g of N³⁻ ion contains 10NA electrons

where NA - Avagadro number

so, 1 g of N³⁻ ion =10NA/14

∴4.2g of N³⁻ ion =4.2x 10NA/14

=3NA

∴The total number of electrons in 4.2g of N3- ion 3NA

Explanation:

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