Question

How many electrons are present in 16g of CH4? Pls solve this problem plss

Answer 1

CH₄(methane)

Molar mass = 12 + 4 = 16 g

1 mole of CH₄ contains 6.022 x 10²³ atoms in 16 g

1 atom contains 6 + 4 = 10 electrons

6.022 x 10²³ atoms have 6.022 x 10²⁴ electrons

Answer 2

Answer: $6.023\times 10^{24}$

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 Liters at STP and contains avogadro's number $6.023\times 10^{23}$ of particles.

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}$

$\text{Number of moles of}CH_4=\frac{16g}{16g/mol}=1mole$  

No of electrons in $CH_4$ = 6 + 4 = 10

1 mole of $CH_4$ contains =$10\times 6.023\times 10^{23}=6.023\times 10^{24}$  electrons

Thus $6.023\times 10^{24}$  electrons are present in 16 g of $CH_4$.