How many electrons are present in 180 gm. of water
Answers
Answered by
3
Answer:
In one molecule of water there are total 1+1+8=10 electrons..and in mole of water there are Na * 10 electrons...so now we have 180 gm of water....so first calculate no of moles i.e 180/(18) = 10 moles...Therefore required no of electrons= 10 * Na * 10= 10*6*10^23*10 electrons(calculate this on your copy)
Answered by
2
Answer:
Molecularly there are 540 electrons in 180 gm of water
Explanation:
one hydrogen and two oxygen molecule is water (H2O) and hence 180 grams contain 180 ×3 = 540
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