Chemistry, asked by Muskan8592, 11 months ago

How many electrons are present in 180g of water?

Answers

Answered by Sumit15081947

10

Answer:180gm of water =10 moles of water

1 mole =6.022 x 10*23 atoms

1 atom of water has 18 elecrons

hence, total elecrons=10 x 6.022 x 10*23 x18=1.083 x 10*26

Explanation:

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