Question

how many electrons are present in 2×10^-3 mole of oxygen​

Answer 1

one atom of oxygen has 8 electron as its atomic number is 8.

no of atom in 1 mole=6.022*10²³

no of atom in 2*10-³ mole=1.2044*10²¹

no of electron=1.2044*10²¹*8

= 9.6352*10²¹ electron

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Answer 2

Given :

No. of moles of Oxygen = 2 × 10³

To Find :

Number of electrons present in 2 × 10³ moles of oxygen

Solution :

We know, 8 × 6.022 × 10²³ electrons are present in 1 mole of oxygen.

So, using unitary method,

As, 1 mole of Oxygen has 8×6.022×10²³ electrons

    2 × 10³ mole will have $\frac{8}{1}$×6.022×10²³×2×10³ electrons

                                      = 96.35 × 10²⁶ electrons

                                      =  9.635 × 10²⁷ electrons

Therefore, 2×10³ moles of oxygen contains 9.635 × 10²⁷ electrons.