Question

How many electrons are present in 22 g of CO2?

Answer 1

Answer:

Molar mass of CO2= 44.01 g

=44g

Therefore, 44g of Co2 has 6.022×10^23 molecules

22g has 6.022×10^23/44×22

=3.011×10^23 molecules.

Answer 2

The number of electrons present in 22 g of CO2 is 66.22* 10²³.

Given:-

Mass of CO2 = 22g

To Find:-

The number of electrons present in 22 g of CO2.

Solution:-

We can easily find out the number of electrons present in 22 g of CO2 by using the following procedure.

As

Mass of CO2 (m) = 22g

Molar mass of CO2 (w) = 44g

Before calculating the number of electrons in 22g of CO2, first, we need to find out the number of moles of CO2.

$moles = \frac{mass}{molar \: mass}$

$n = \frac{m}{w}$

$n = \frac{22}{44}$

$n = \frac{1}{2}$

$n = 0.5$

Now, 1 CO2 contains = 6+8+8 electrons

1 CO2 contains = 22 electrons

1 mole CO2 contains = 22 mol electrons

0.5 mole CO2 contains = 22 mol electrons * 0.5

0.5 mole CO2 contains = 11 mol electrons

0.5 mole CO2 contains = 11 * Na electrons

$N = 11 \times 6.02 \times {10}^{23}$

$N = 66.22 \times {10}^{23} electrons$

Hence, The number of electrons present in 22 g of CO2 is 66.22* 10²³.

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