Question

How many electrons are present in 4.8 g of Ozone?​

Answer 1

Answer:

Mass of ozone=4.8g

Molar mass of ozone(O3) =16*3=48

no of moles of ozone=mass of ozone/molar mass of ozone

Therefore, no of moles of ozone=4.8/48=0.1mol

1 mole of ozone =6.022* 10^23 electrons

so,

0.1 mole of ozone=0.1*6.022*10^23=6.022*10^24 electrons

Hope it's clear to you

Answer 2

Given :

Mass of Ozone (O₃) = 4.8 gm

To Find :

How many electrons are present in 4.8 g of Ozone?​

Solution :

No. of moles in 4.8 gm of O₃ = $\frac{Given Mass}{Molar Mass}$

                                                 = $\frac{4.8}{48}$

                                                 = 0.1 mole

No. of molecules in 0.1 mole of O₃ = 0.1 × 6.022 × 10²³

                                                         = 6.022 × 10²² molecules

One molecule of O₃ contains 24 electrons

6.022 × 10²² molecules of O₃ will contain 24×6.022×10²² electrons

                                                                  = 144.528 × 10²² electrons

                                                                  = 1.445 × 10²⁴ electrons

∴ The number of electrons present in 4.8 gm of Ozone is 1.445 × 10²⁴