how many electrons are present in 5 kg of iron
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more than 2 electrons are present in 5 kg of iron
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Find the number of moles first
• n = m/M = 5000/56 = 89.29
• total number of Fe atoms = 89.29 x 6.022 x 10^23
• A single Fe atom contains 26 electrons , therefore , Total number or Fe atoms = 89.29x6.022x10^23 x 26
( hope u will solve for the final value )
• n = m/M = 5000/56 = 89.29
• total number of Fe atoms = 89.29 x 6.022 x 10^23
• A single Fe atom contains 26 electrons , therefore , Total number or Fe atoms = 89.29x6.022x10^23 x 26
( hope u will solve for the final value )
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