Question

How many electrons are there in charge of 3.2 × 10^-19 C​

Answer 1

Answer:

Given charge on one electron = -1.6\times10^{(-19)}\text{ C}

Conductor possesses a positive charge of =3.2\times10^{(-19)}\text{ C}

Therefore,

No. of electrons = \frac{3.2\times10^{-19}}{1.6\times10^{-19}} = \frac{3.2}{1.6} =2

Since the charge on the conductor is positive, the conductor is 2 electrons short.

Answer 2

$\huge\sf{ \underline{ \underline{Question}}}$

How many electrons are there in charge of $\sf{3.2\times \ 10^{-19}}$ C

$\huge\sf{ \underline{ \underline{Answer}}}$

$\sf{Two}$

$\huge\sf{ \underline{ \underline{Concept \:Used}}}$

★$\sf{ \boxed{q\:=\:ne}}$

$\huge\sf{ \underline{ \underline{Solution }}}$

$\sf{q\:=\:ne}$

• q = charge
• n = number of electrons
• e = charge on electron

________________________________

$\mapsto\sf{q\:=\:ne }$

$\sf{Put\:value\:of\:q\:and\:e }$

$\mapsto\sf{3.2\times \ 10^{-19}\:=\:n\times 1.6 \times \ 10^{-19}}$

$\mapsto\sf{n\:=\:\dfrac{3.2\times \ 10^{-19}}{1.6\times \ 10^{-19}}}$

$\mapsto\sf{n\:=\:\dfrac{\cancel{3.2\times \ 10^{-19}}}{\cancel{1.6\times \ 10^{-19}}}}$

$\sf{ \boxed{n\:=\:2 }}$