Question

How many electrons can be filled in all the orbitals with n + 1 is equal to 5?

Answer 1

For the 4p orbital, n = 4 and l = 1, therefore (n + l) = 5. As the p subshell has three orbitals and each orbital can hold a maximum of two electrons,

Therefore the maximum number of electrons that would be present in the 4p orbital would be 6.

For the 3d orbital, n = 3 and l = 2, therefore (n + l) = 5

Hope it helps