Question

How many electrons can be present in a shell with n + l = 5?
Plz explain too​

Answer 1

Answer:

( n + I ) =5

Explanation:

For the 5s orbital, n = 5 and I = 0 therefore n+I =5. An a sub shell has only one orbital and as an orbital can hold a maximum of two electrons , therefore the maximum number of electrons that would be present in the 5s orbital would be 2. For the 4p orbital ,n=4 and I =1. Therefore ( n + I ) = 5