Question

How many electrons flow per sec. Through the filament of a 220 v and 110 w electric bulb :-?

Answer 1

Answer:

Voltage(V)= 220V

Power(P)=110W

Current (I)= Power(P)/Voltage (V)

I= 110/220= 0.5 A

Number of electrons flowing per sec(n)=Current (I)/Charge on one electron

n=0.5/(1.6×10^(-19)=0.3125×10^19

n=3.125×10^18

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Answer 2

Explanation:

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