How many electrons flow per second through the filament of an electric lamp which carriesca current of 0.54A
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Answered by
10
Q=?
I=0.54A
t=1 sec.
Q=It
Q=0.54×1
=0.54C
number of electrons That Flow in 1 coulomb of charge=1.6×10^-9
number of electrons That Flow in 0.54 coulomb of charge=0.864×10^-9
I=0.54A
t=1 sec.
Q=It
Q=0.54×1
=0.54C
number of electrons That Flow in 1 coulomb of charge=1.6×10^-9
number of electrons That Flow in 0.54 coulomb of charge=0.864×10^-9
Answered by
10
>To calculate the the no of electron, first we calculate the charge..
q=A×t
q=o.52×1
q=0.52
now we calculate the no of electron..
ne=q
n=q/e
n=0.52/1.6×10^-19
n=0.325×10^19
q=A×t
q=o.52×1
q=0.52
now we calculate the no of electron..
ne=q
n=q/e
n=0.52/1.6×10^-19
n=0.325×10^19
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