Question

(How many electrons flow through a metallic wire if a current of 0.5 A is
passed for 2 hours? (Given: 1F = 96,500C mol-1).​

Answer 1

as we know that I=Q/T

0.5=Q/7,20,000

0.5*7,20,000=Q

3,60,000=Q

as 1 coulomb =6.25 electrons

total no. of electrons =6.25*3,60,000

= 2250000

=2.25×10^6