(How many electrons flow through a metallic wire if a current of 0.5 A is
passed for 2 hours? (Given: 1F = 96,500C mol-1).
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as we know that I=Q/T
0.5=Q/7,20,000
0.5*7,20,000=Q
3,60,000=Q
as 1 coulomb =6.25 electrons
total no. of electrons =6.25*3,60,000
= 2250000
=2.25×10^6
laxitaHelaiya:
please mark it as brainlist only one is left
your ans is different
my ans is 2.25×10^22e sec
Q=3600 hi aate ga
aayega
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