How many electrons flowing per second constitute current of 1 A?
Answers
6.242 x 10^28 electrons constitute a current of q ampere
Explanation:
From the formula of current we know that the units of current are ampere. Where
1 ampere = 1 coulumb per second ............ eq (1)
Now, we know that 1 electron is equal to 1.602 × 10-19 coulumbs. So,
1 coulumb = 1/ 1.602 × 10-19 electrons = 6.242 x 10^28
So, putting value in eq (1). We get,
1 ampere = 6.242 x 10^28 electrons per second
Given:
The current, I = 1 A
To Find:
The no of electrons flowing per second.
Calculation:
- The charge on 1 electron = 1.6 × 10⁻¹⁹ C
⇒ No of electrons in 1 Coulomb charge = 1 / 1.6 × 10⁻¹⁹
⇒ No of electrons in 1 C charge = 0.625 × 10¹⁹
- Charge flowing in 1 Ampere current = 1 Coulomb / second
⇒ No of electrons flowing in 1 Ampere = 0.625 × 10¹⁹ = 6.25 × 10¹⁸
- So, there are 0.625 × 10¹⁹ electrons flowing per second in a current of 1 A.