How many electrons have to be removed to ionize 1.0∈-6 mol of Ne atoms to Ne+ ions in a neon advertising tube
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In a neon advertising tube, how many electrons have to be removed to ionise 1.0 × 10^-6 mol of Ne atoms to Ne+ ions?
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Well, look at your stoichiometric equation…
Ne(g)+Δ→Ne+(g)+e−
If we ionize a MOLE of neon atoms, then we get a mole of neon cations, AND a mole of electrons; conservation of mass and charge ASSURES this outcome. If we ionize a DOZEN neon atoms, then we get a DOZEN neon cations, AND a DOZEN electrons. And so should we ionize 1.0×10−6∙mol neon atoms, then we get 1.0×10−6∙mol neon CATIONS, AND a 1.0×10−6∙mol quantity of electrons…
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