Question

how many electrons in 3d and 4f sub shell​

Answer 1

Answer:

This means that the s orbital can contain up to two electrons, the p orbital can contain up to six electrons, the d orbital can contain up to 10 electrons, and the f orbital can contain up to 14 electrons.

Explanation:

please drop some thanks for me

and make me as brainlist please

Answer 2

Answer:

For F, L= 3 orbital angular momentum= n-1 where n is 4 , the principal quantum number.g

For F, L= 3 orbital angular momentum= n-1 where n is 4 , the principal quantum number.gSo its occupation number is 2(2L+1)=14 elevtrons.

For F, L= 3 orbital angular momentum= n-1 where n is 4 , the principal quantum number.gSo its occupation number is 2(2L+1)=14 elevtrons.Or J = L+S.occ.no.= 2J +1

For F, L= 3 orbital angular momentum= n-1 where n is 4 , the principal quantum number.gSo its occupation number is 2(2L+1)=14 elevtrons.Or J = L+S.occ.no.= 2J +1So 4F has two J values

For F, L= 3 orbital angular momentum= n-1 where n is 4 , the principal quantum number.gSo its occupation number is 2(2L+1)=14 elevtrons.Or J = L+S.occ.no.= 2J +1So 4F has two J valuesJ=L+S or L-S, so either 7/2 or 5/2

For F, L= 3 orbital angular momentum= n-1 where n is 4 , the principal quantum number.gSo its occupation number is 2(2L+1)=14 elevtrons.Or J = L+S.occ.no.= 2J +1So 4F has two J valuesJ=L+S or L-S, so either 7/2 or 5/2So elect.no. is 8 and 6 respectively.

For F, L= 3 orbital angular momentum= n-1 where n is 4 , the principal quantum number.gSo its occupation number is 2(2L+1)=14 elevtrons.Or J = L+S.occ.no.= 2J +1So 4F has two J valuesJ=L+S or L-S, so either 7/2 or 5/2So elect.no. is 8 and 6 respectively.So the total is 14 electrons.

For F, L= 3 orbital angular momentum= n-1 where n is 4 , the principal quantum number.gSo its occupation number is 2(2L+1)=14 elevtrons.Or J = L+S.occ.no.= 2J +1So 4F has two J valuesJ=L+S or L-S, so either 7/2 or 5/2So elect.no. is 8 and 6 respectively.So the total is 14 electrons.4.2K views

For F, L= 3 orbital angular momentum= n-1 where n is 4 , the principal quantum number.gSo its occupation number is 2(2L+1)=14 elevtrons.Or J = L+S.occ.no.= 2J +1So 4F has two J valuesJ=L+S or L-S, so either 7/2 or 5/2So elect.no. is 8 and 6 respectively.So the total is 14 electrons.4.2K viewsView upvotes

For F, L= 3 orbital angular momentum= n-1 where n is 4 , the principal quantum number.gSo its occupation number is 2(2L+1)=14 elevtrons.Or J = L+S.occ.no.= 2J +1So 4F has two J valuesJ=L+S or L-S, so either 7/2 or 5/2So elect.no. is 8 and 6 respectively.So the total is 14 electrons.4.2K viewsView upvotesRelated Questions (More Answers Below)