how many electrons in an atom with atomic number 105 can have ( n + l ) = 8
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Answered by
61
Hi
total electron is 105
it is dubnium
the outhermost shell is 5f^14,6d^3,7s^2
in case of 5f
n+l=5+3=8
for6d
6+2=8
7s
7+0=7
so n+l =8 is possible but not outermost shell
total electron is 105
it is dubnium
the outhermost shell is 5f^14,6d^3,7s^2
in case of 5f
n+l=5+3=8
for6d
6+2=8
7s
7+0=7
so n+l =8 is possible but not outermost shell
Answered by
82
Explanation:
We are given that total number of electrons = 105
Therefore, the element is dubnium. The electronic configuration of the outermost shell of this atom would be .
We are also given that n+l=8
So, for 5f shell, we know 5+3=8. So, the number of electrons in 5f shell is 14.
For 6d, 6+2=8 and so we know that there are 3 electrons in the outermost shell.
The total number of electrons = 14 + 3 = 17
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