How many electrons must be added to charge a body with magnitude 3.6 *10^18 C?
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Answer:
you can solve it using a formula Q = ne
Where Q is charge transferredn is the no. Of electrons transferred
And e is the charge on 1 electron
Q = 3.6* 10^18coulomb
And e is 1.6 * 10^ -16
Now u can calculate n
Explanation:
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