How many electrons must be added to one plate and removed from other so as to store 25.0 J of energy in a 5.0 nF J parallel plate capacitor
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E needed to be stored in capacitor is given by q²/2c
find q by substituting values (q=√2EC)
one electron has a charge of 1.6 x 10^-19 coulomb ( I guess)
hence you can then solve for number of electrons
find q by substituting values (q=√2EC)
one electron has a charge of 1.6 x 10^-19 coulomb ( I guess)
hence you can then solve for number of electrons
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