Physics, asked by joban6597, 7 months ago

How many electrons must be removed from the sphere to give it a
charge of +2 microcoulomb. is there any change in the mass when it is given this
positive charge. How much i
s this charge

Answers

Answered by aristocles
8

Answer:

Number of electrons removed from the sphere is

N = 1.25 \times 10^{13}

Due to removal of electrons sphere mass will decrease

Change in the mass of sphere is given as

\Delta m = 1.14 \times 10^{-17} kg

Explanation:

As we know that the charge is

Q = 2 \mu C

Now we know by the quantization of charge is given as

Q = Ne

(2 \times 10^{-6}) = N(1.6 \times 10^{-19})

now we have

N = \frac{(2\times 10^{-6})}{1.6 \times 10^{-19}}

N = 1.25 \times 10^{13}

now we know that when electrons are removed from sphere then it will get positive charge on it

so we can say that the mass of the sphere will get reduced due to removal of electrons

So we have

\Delta m = N m_e

\Delta m = (1.25 \times 10^{13})(9.1 \times 10^{-31})

\Delta m = 1.14 \times 10^{-17} kg

#Learn

Topic : Charge

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