Question

how many electrons pass through a conductor in 0.2sec , if the current passing through it is 0.5 ampere .

Answer 1

charge=current*time
charge=0.5*0.2
charge=0.1 coulumb
we have q=ne
0.1=n(1.602*10^-19)
n=0.1/1.602*10^-19
by dividing we get
n=0.0624*10^19
n=6.24*10^17

Answer 2

Answer:

I=0.5A

T=0.2 sec

I=Q/t

Q=It

Q=0.5*0.2

Q=0.1 c

Q=ne

I=ne/t

n=It/e

n= 0.5*0.2/1.6*10^-19. (e=1.6*10^-19)

(fix valve of e.)

after dividing the eqns .

the Answer =

[6.25 *10^17]